Question

Question
For the figure shown below, compute the voltage drop across the resistor 13H10)​

Answer 1

Answer:

R3andR4 are in series. The combined resistance is 400Ω.

Now R2(−100Ω)and400Ω resistance are in parallel. The

combined resistance is (100×400)/500=80Ω.

Total resistance is R=80+50=130Ω

I=65/130=1/2A.

So, V=IR1=1./2×50=25V