Question

Question from current electricity class 12 solve it fast

Answer 1

Answer

• 0.33 Amperes

Explanation

See attachment for clear vision on diagram

i₁ = i₂ + i₃ ... (1)

Using 1st loop :

3i₁ + i₃ = 6

⇒ 3i₂ + 3i₃ + i₃ = 6 [ From (1) ]

⇒ 3i₂ + 4i₃ = 6 ... (2)

Using 2nd loop :

2i₂ - i₃ + 3i₂ = 9

⇒ 5i₂ - i₃ = 9

⇒ 20i₂ - 4i₃ = 36 ... (3) [ Multiply with 4 ]

Now solve (3) + (2) , we get ,

⇒ 20i₂ + 3i₂ + 4i₃ - 4i₃ = 36 + 6

⇒ 23i₂ = 36

⇒ i₂ = 1.56 A

Sub. i₂ value in (2) , we get ,

⇒ 3(1.56)+4i₃ = 6

⇒ 4.68 + 4i₃ = 6

⇒ 4i₃ = 1.32

⇒ i₃ = 0.33

Sub. i₂,i₃ values in (1), we get ,

⇒ i₁ = 1.56 + 0.33

⇒ i₁ = 1.89

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Now current passing through 1 Ω resistor is i₃

⇒ i₃ = 0.33 Amperes