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Are f and g both necessarily onto, if gof is onto?
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No its not necessary for g and f to be both onto for gof is onto as onto cant be determined like this, for onto a specific range is provided and if the gof lies between the provided range it can be onto as if
F=sinx and G= |x|
And it is given that R- [0, 1]
Then gof comes |sinx|
and it is onto as it lies between [0,1]
But g and f are not both onto.
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Answered by
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Explanation:
let
f : A --> B
g : B --> C
let
C belongs to c
since gof : A --> C , A belongs to a
gof(a) = c => g(f(a)) = c
g : B --> C ,
B belongs to f(a) for any C belongs to c
there exist an element belonging to B
hence g is onto but f is not onto .
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