Question

t^2-20t-96=0 find t​

Answer 1

Answer:

${t}^{2} - 20t - 96 = 0 \\ splitting \: the \: middle \: term \\ {t}^{2} - 12t - 8t - 96 = 0 \\ t(t - 12) - 8(t - 12) = 0 \\ (t - 12)(t - 8) = 0 \\ (t - 12) = 0 \: or(t - 8) = 0 \\ t = 12 \: or \: t = 8$

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Answer 2

${t}^{2} - 20t - 96 = 0$

${t}^{2} + 24t - 4t - 96 = 0$

$t(t + 24) - 4(t + 24) = 0$

(t+24)(t-4) = 0

then t = -24 & 4