QUESTION FROM QUADRATIC EQUATION
PLEASE SHOW HOLE PROCESS
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the question is to factorise the equation. 16x^2-24x=0 (divide whole equation by 8)
the equation will be x^2-3x +0=0
therefore, we have to find 2 numbers such that if multiplied the product is 0 & if added,the sum is -3.
hence the numbers are 0 & -3 so we have to spilt 3x into 0x &-3x
therefore,x^2-3x+0x+0=0
x(x-3)-0(x-3)=0
(x-3)(x-0)=0
hence,x=3 or x=0
please mark my answer as brainliest.
hope it helps....please feel free to ask any doubts
the equation will be x^2-3x +0=0
therefore, we have to find 2 numbers such that if multiplied the product is 0 & if added,the sum is -3.
hence the numbers are 0 & -3 so we have to spilt 3x into 0x &-3x
therefore,x^2-3x+0x+0=0
x(x-3)-0(x-3)=0
(x-3)(x-0)=0
hence,x=3 or x=0
please mark my answer as brainliest.
hope it helps....please feel free to ask any doubts
dhonisuresh0703:
please mark my answer as brainliest
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