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102 degrees
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Step-by-step explanation:
In given figure parallelogram PQ RS , PR and RS diagonal intersect at O
we know that the diagonal intersect at right angle each other .
The line LM is parallel to PS .
Then diagonal of parallelogram divided in equal area of triangles
Then area POQ = area of POS = area of QOR = area of SOR .
or area of POS+area of QOR= ½ = area of parallelogram
then area of POS+area of QOR=area of QOR=area of POQ + area of POQ + area of SOR
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