Question

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Potential difference between two points of a wire carrying 2 Ampere current is 0.1 volt. calculate the resistance between these points .

Answer 1

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Solution Given here.
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From Ohm's law we have :

$\frac{potential \: \: \: difference}{current} = resistance \\ \\ or \\ \\ \frac{v}{i} = r$

here , potential difference , v = 0.1 volts

current , I = 2 amperes

and resistance, r = ?

putting these values in the above formula , we get :

$\frac{0.1}{2} = r \\ \\ 0.05 = r \\ \\ or \: \\ resistance \: \: r \: = 0.05 \: \: ohm \:$
or ( 0.05 Ω )

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