Question: How to find the nth derivative of sin^4 (x)?
Answer:y=sin4x=(1−cos2x2)2=14⋅[1+cos22x−2cos2x]
=14⋅[1+1+cos4x2−2cos2x]
⟹y=18⋅[3+cos4x−4cos2x]
∴y′n=18⋅[4n⋅cos(4x+nπ2)−4⋅2n⋅cos(2x+nπ2)]
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Answer:
14 (1++cos42-2cos2*y1
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Step-by-step explanation:
nth derivatives of Sin4x
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