Math, asked by ruchitaalle318, 8 months ago

Question
If
3x - 4/x = 4; and x not equal to 0 find: 27x^3- 64/x^3


Answers

Answered by roatveer
1

Answer:

when factors 3x-4/x=4

x=2 and -2/3

and after putting in second equation

answer is 208 on both side

Answered by vijayapravallikapatt
4

3x - 4/x = 4

3x^2 - 4x - 4 = 0

3x^2 - 6x + 2x - 4 = 0

3x(x - 2) + 2(x - 2) = 0

3x + 2 = 0 and x - 2 = 0

x = -2/3 and x = 2

x = -2/3

27x^3 - 64/x^3

27(-2/3)^3 - 64/(-2/3)^3

27(-8/27) - 64(27)/(-8)

-8 + 8(27)

8(-1 + 27)

8(26)

208

x = 2

27x^3 - 64/x^3

27(2)^3 - 64/(2)^3

27(8) - 64/(8)

27(8) - 8

8(27 - 1)

8(26)

208

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