Question

✯ Question :-
If the sum of two positive square are 765. Also, the first square is greater than other by 3. Then find the number​

Answer 1

Explanation:

Let the two numbers be 'a' and 'b'.

Now as numbers are distinct, one of them would be greater than the other. Assume any number to be bigger as it will not affect the result.

Let a > b

Now,

Given, a + b = 85 …1

& a - b = 9 …2

As we know by theorm,

a^2 - b^2 = (a+b)*(a-b) …3

Putting values from (1) & (2) in (3)

Therefore, a^2 - b^2 = 85*9 = 765 ans

The ans to the ques. is 765.

Alternate solution :-

This is lengthy but basic one

Continuing after (1) & (2)

Adding both,

(a+b)+(a-b) = 85 + 9

2a = 94 => a = 47

Putting in (2)

b = 38

Solving a^2 - b^2 will yeild same result of 765.

This method demands more calculations.

Hence for this ques., first method is fine sol.

Answer 2

Answer:

Ohh maths kar rahe the .

sorry mai offline ho gayi thi actually meri sis ne phone le liya tha