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There are two cases possible. When angle AOB + angle BOC is more than 180° and when it is less than 180°.
See both cases and their solutions.
Proved. Done.
There are two cases possible. When angle AOB + angle BOC is more than 180° and when it is less than 180°.
See both cases and their solutions.
Proved. Done.
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kvnmurty:
:-)
Answered by
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Heya User,
--> I'm Lazy to add pics so, guess, you better do some homework ^_^
=_+ Now,
-->∠AEC = 180° - ∠EAC - ∠ECA
=> 2∠AEC = 360° - 2∠EAC - 2∠ECA
=> 2∠AEC = 360° - 2∠BAC - 2∠DCA
However, we know that the angle made by a chord on the center is double of that made at the circumference ...
=> 2∠AEC = 360° - ∠BOC - ∠AOD
=> 2∠AEC = ∠BOD + ∠AOC --> [ ∠AOC > 180° is the major angle ]
However, when ∠AOC < 180° , ∠BOD takes its place :) ..
And Hence, we are done ..
--> I'm Lazy to add pics so, guess, you better do some homework ^_^
=_+ Now,
-->∠AEC = 180° - ∠EAC - ∠ECA
=> 2∠AEC = 360° - 2∠EAC - 2∠ECA
=> 2∠AEC = 360° - 2∠BAC - 2∠DCA
However, we know that the angle made by a chord on the center is double of that made at the circumference ...
=> 2∠AEC = 360° - ∠BOC - ∠AOD
=> 2∠AEC = ∠BOD + ∠AOC --> [ ∠AOC > 180° is the major angle ]
However, when ∠AOC < 180° , ∠BOD takes its place :) ..
And Hence, we are done ..
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