Question - In the figure, C is a point on the minor arc AB of the Circle with centre O. Given angle ACB = p°, angle AOB = q°, express q in terms of p. Calculate p if OACB is a parallelogram.
Please solve this problem using Arc and Chord properties of Circle.
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Construction:Draw angle AOB and angle ACB
Given that:AB is minor arc and angle ACB=p nd AOB=q
as per theorem of angle substended by an arc its centre is twice the angle is substence at circumference
angle 2p=360-q so,
p=180-q/2........(i)
if ACBO is a parallelogram then angle p=q
also from (i) p=180-q/solving the equation we get...,
360=3q
q=120°
p=q...so,
p=120°
Given that:AB is minor arc and angle ACB=p nd AOB=q
as per theorem of angle substended by an arc its centre is twice the angle is substence at circumference
angle 2p=360-q so,
p=180-q/2........(i)
if ACBO is a parallelogram then angle p=q
also from (i) p=180-q/solving the equation we get...,
360=3q
q=120°
p=q...so,
p=120°
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