Question

Question Is Below (pls answer)

Answer 1

Given

• BE=2 km
• DC=3 km
• DE=2 km
• EF=2 km
• AF= 6 km

To Find

• Area of the Town in Square Kilometres

Step by step explanation

Now in ∆ ABH

• Height (AB) = 6-2-2=2 km
• Base ( HB) = 4+3= 7 km

Area of ∆ ABH= 1/2 Base × Height

Area of ∆ ABH= 1/2 ×7×2

Area of ∆ ABH= 7 Km²

Now in Rectangle BCHG We have,

• Length (GC) = 4+3=7 Km
• Breadth (BC) = 2 Km

Area of Rectangle BCHG = Leghth × Breadth

Area of Rectangle BCHG = 7 km ×2 km

Area of Rectangle BCHG = 14 cm²

Now In Rectangle DEFG We have,

• Length (EF)= 4 km
• Breadth (DE) = 2km

Area of Rectangle DEFG= Length× Breadth

Area of Rectangle DEFG= 4×2

Area of Rectangle DEFG= 8 km²

• Area of the Town in Square Kilometres= Area Of ∆ ABH + Area Of Rectangle BCHG + Area of Rectangle DEFG
• Area of the Town in Square Kilometres= 7+14+8 Km²

• Area of the Town in Square Kilometres= 29 Km²