Question

QUESTION is:
Find the amount if Rs.40000 are invested for 2 years at 2 1/2 % compound interest.

Answer is this question is:42025
​

Answer 1

Step-by-step explanation:

Given:

Principle =  Rs.40000

Time =   2 years

Rate = 2 1/2% = 2.50%

Formula:

$A$=$P(1+R/100$$)^{n}$

A = amount

P = principle

R = rate of interest

n = times of years

Calulation:

A= $40000(1+2.50/100)^2$

A = $40000(1+0.025)^2$

A = $40000(1.025)^2$

A = 40000(1.050625)

A = 42025

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Answer 2

Answer:

Principal(P)=Rs. 4000

Rate(

R

1

)=10% and (

R

2

)=15%

time(t)= 2 years

Amount=

P

(

1

+

R

1

100

)

(

1

+

R

2

100

)

=

R

s

.

4000

(

1

+

10

100

)

(

1

+

15

100

)

=

R

s

.

4000

×

11

10

×

23

20

=

R

s

.

5060

C.I.= Amount-Principal

=Rs. 5060 -Rs. 4000=Rs. 1060

Step-by-step explanation:

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