QUESTION :-
It is desried to prepare 500 g of solution. with 10% urea in water. How much urea should we dissolve in how much volume of water?(density of water is 1 ml)
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Answers
Answer:
The mass by mass percentage of a solution is given by the following relation
Mass by mass percentage of a solution=
(Mass if solute/ mass of solution)×100
Where mass of the solution=mass of the solute +mass of solvent
We have to prepare 500g of 10%mass by the mass percent solution of urea in water Let the mass of urea required be 'a' grams.
(a /500)×100=10
Solving for a, we get
a=50g.
Thus, mass of urea is 50g. So, mass of water will be
=(500-50g) =450g
Since the density of water is given to be 1gml-1, therefore the volume of water required would be
= Mass of the water / density of water
= 450/ 1=450ml.
Hence the mass of urea required would be 50g and the volume of water required would be 450 ml.
hope this will be helpful to you
Answer:
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