Question

Question :-

★Moderator
★Brianly stars
★Maths aryabhatta
★Other best users

Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:

(a) broke even,
(b) lost 4 cents,
(c) gained 4 cents,
(d) lost 10 cents,
(e) gained 10 cents​

Answer 1

Ok let's assume the price of one pipe is x

$profit \: on \: one \: pipe \: = 20 \: percent \: \\ so \: percentage \: of \: it \: according \: to \: c.p \: = \frac{12 \: x}{10} \\ \frac{12 \: x \: }{10} \: = 1.20 \\ x \: = \frac{12.0}{10} = 1.0$

Let's assume C.P of pipe on which loss was incurred is y

$loss \: on \: pipe \: = 20 \: percent \\ so \: percentage \: of \: it \: according \: to \: c.p \: = \frac{8y}{10} \\ \frac{8y}{10} = 1.20 \\ y = \frac{12}{8} = 1.5$

So we can see the loss occurred on y is 30 cents and profit occurred on x is 20 cents

So overall loss : 10 cents

Mark as brainliest. Thanks

Answer 2

For 1st pipes, S.P =1.20 , profit =20 %

C.P=S.P−profit

CP=1.20−20%×CP

∴120% CP=1.20

∴CP= $\large\frac{1.20}{120}$ ×100

∴CP¹ =1.00

For 2nd =s.p+loss

CP=1.20+200 % CP

∴80% CP=1.20

∴CP= $\large\frac{1.20}{80}$×100

=1.50

∴ Total CP=1.00+1.50=2.50

Total SP=1.20+1.20=2.40

∴ He suffered 10 cents loss.

Answer : (d) lost 10 cents

____________

Can I get your Intro -,-"

Mine - Sanjeet , 7th , From Maharashtra ¡¡