Question

Question No. 03
Multiple Choice ( Select 1 out of 4 options for the question below)
The circuit shown in the Fig is in steady state when the switch is closed at 1 = 0 Assuming that the inductance is ideat the current through the
1 Ω
inductor at t = 0+ equals
t=0
5 V-
- uF 3422​

Answer 1

Answer:

Inductor is open circuited at t=0 and short circuited at t=∞

Hence, I

1

=

10R

10V

=1A

I

2

=

8R

10V

=

8

10

A

So,

I

2

I

1

=

8

10

1

=

10

8

=0.8