Math, asked by birinder, 1 year ago

Question no.1,2,3,4,5,6,7,8,9,10

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Answered by sharmabr001
1
Second only 4√81-8√216+15 5√32+√225
Now write 81,216,32,225as product of prime
I) 81=3*3*3*3
ii) 216=2*2*2*3*3*3
iii)32=2*2*2*2*2
iv)225=3*3*5*5

I) forth root of 81=(81)¼=(3^4)¼=3^(4+¼)=3

ii) ³√216=(216)⅓=(2³*3³)^⅓)=[(2*3)³]^⅓=(2*3)=6

iii)fifth root of 32=(32)^1/5=(2^5)^
1/5=2

iv)√225=√(3*3)*(5*5)=3*5=15

forth root of 81-8 ³√216+15 fifth root of 32+√225
=3-(8*6)+(15*2)+15 [from (I)and(iv)]
=3-48+30+15
=48-48
=0
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