Question no 10 plzzz fast
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Answer:Let 3-3√7 be a rational number where and b are integers having no common factor and b is not equal to 0
Step-by-step explanation:3-3√7=a/b
3√7=a/b -3
3-√7=a-3b by B
√7=a-3b by 2b
Since a n b are integers
Therefore a-3b by 2b is rational
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Step-by-step explanation:
we know that √7 is an irrational no.
let 3-3√7 = a/b ( where a and b are the integers)
now
3-a/b= 3√7
(3b-a)
_____ = √7
b
as a and b are integers so (3b-a)/b should be a rational no. and so √7 should also be a rational no. .but this will contradict the fact that √7 is an no. this contradiction has occur becoz of our wrong assumption
so we conclude that 3-3√7 is an irrational no.
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