Question

Question no. 105: How much force is needed to hold a
1000 kg iron anchor, when it is completely immersed in
seawater of density 1.03 x 109 kg/m®? (Density of iron is
7.8 x 10 kg/m)
1) 8508 N
2) 850.8 N
3) 1293 N
4) none of these​

Answer 1

Answer:

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Answer 2

Explanation:

Given How much force is needed to hold a 1000 kg iron anchor, when it is completely immersed in  seawater of density 1.03 x 10^3 kg/m®?  

• Principle of Archimedes states when a body is immersed partially or completely in a liquid it experiences an apparent loss in weight which is equal to the weight of the fluid displaced by the body.
• So density of iron = 7870 kg/m^3
• So density = mass / volume
• Volume of anchor will be 1000 / 7870 = 0.127
• So volume of water displaced is equal to the volume of anchor.
• Now weight of water displaced  
•                                mass = volume x density
•                                        = 0.127 x 1030 x 9.81
•                                       = 1283.90 N
• Weight of anchor in air = 1000 x 9.81
•                                         = 9810 N
• So weight of anchor in water = 9810 – 1283.90
•                                                    = 8526.1 N
• Therefore the force required to support the anchor in water will be 8526.1 N

Reference link will be

https://brainly.in/question/26248778