Question

Question no.-14,15,16
accurate answer will be marked as braianliest ..

Answer 1

(14). First:-. area of triangle (ABC)=area of triangle (ACE)
because they lie on same base and between same parallel .
so they are equal now if we add area of triangle (ADC) in both so:-
(ADC)+(ABC)=(ADC)+(ACE)
(ABCD)=(ADE)
hence proved.................
(15). First in quadrilateral (CDQP)
(DQC)=(DPC) and they also lie on same base(DC)
if their base is same area is same then their height should be also same .....
And if height. from (DQ) is equal to height of (CP) means they are parallel lines ......so it's a trapizum.....
And similarly you can find the height of triangle (ACD) and (BDC) by
subtracting (ACQ)-(QCD)=(BDP)-(CDP)
(ACD) =(BDC)

Answer 2

Answer:

dB SPL you mate and mark me as brainliest hope you understand and mark me as brainliest hope you understand and mark me as brainliest hope you understand