QUESTION NO.15
I WILL MARK AS BRAINLIEST IF U SOLVE IT CORRECT
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let the ordinate be k
now as per the question it's anaconda is 1*1/2 of. k
therefore 3/2* k
it's points will be (3/2*k , k)
2x+5y=19
put value
2( 3/2 *k) + 5k = 19
3k+ 5k=19
k= 19/8
x abscissa= 3/2 * k
= 3/2 * 19/8
= 3.5
x= 3.5
y=2.3
now as per the question it's anaconda is 1*1/2 of. k
therefore 3/2* k
it's points will be (3/2*k , k)
2x+5y=19
put value
2( 3/2 *k) + 5k = 19
3k+ 5k=19
k= 19/8
x abscissa= 3/2 * k
= 3/2 * 19/8
= 3.5
x= 3.5
y=2.3
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Answered by
2
2X +5Y = 19...........(1)
given, ordinate = 3/2 of abscissa
that means Y = 3/2 × X......(2)
so substitute it in the first equation
2X + X(5 × 3/2) =19
2X + 15/2 X = 19
(4X +15X) / 2 =19
19X = 38
X=38/19=>2
X=2
now substitute the X value in second equation
Y = 3/2 X
Y = 3/2 × 2
Y = 3
(X,Y) = (2,3)
given, ordinate = 3/2 of abscissa
that means Y = 3/2 × X......(2)
so substitute it in the first equation
2X + X(5 × 3/2) =19
2X + 15/2 X = 19
(4X +15X) / 2 =19
19X = 38
X=38/19=>2
X=2
now substitute the X value in second equation
Y = 3/2 X
Y = 3/2 × 2
Y = 3
(X,Y) = (2,3)
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