question no 16 and 19 plz help its urgent
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16. area of the carpet is 8×5 = 40 m²
and area of the border = 12 m²
area without border = 28 m²
it is equal to (L -2W)(B - 2W)
A/q
(L -2W)(B - 2W) =28
⇒LB -16W -10W +4W² =28
⇒40 -16W -10W +4W² =28
⇒4W² -26W +12 =0
⇒2W² -13W +6 =0
⇒2W²- 12W -W +6 =0
⇒2W(W- 6) -1(W-6) =0
⇒(2W-1)(W-6)=0
⇒W =0.5 m as 6m is more than the breadth
19.
area of the walls = 7560/30 = 252 m²
floor area = 1620/15 =108 m²
∴L×B = 108 m²
⇒B = 9 m
now area of four wall = 2LH + 2BH = 252
⇒2H (L +B ) =252
⇒H =252/42 = 6m
and area of the border = 12 m²
area without border = 28 m²
it is equal to (L -2W)(B - 2W)
A/q
(L -2W)(B - 2W) =28
⇒LB -16W -10W +4W² =28
⇒40 -16W -10W +4W² =28
⇒4W² -26W +12 =0
⇒2W² -13W +6 =0
⇒2W²- 12W -W +6 =0
⇒2W(W- 6) -1(W-6) =0
⇒(2W-1)(W-6)=0
⇒W =0.5 m as 6m is more than the breadth
19.
area of the walls = 7560/30 = 252 m²
floor area = 1620/15 =108 m²
∴L×B = 108 m²
⇒B = 9 m
now area of four wall = 2LH + 2BH = 252
⇒2H (L +B ) =252
⇒H =252/42 = 6m
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SECONDARY SCHOOL MATH 5+3 PTS
Question no 16 and 19 plz help its urgent
by Khushi31 39 minutes ago
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16. area of the carpet is 8×5 = 40 m²
and area of the border = 12 m²
area without border = 28 m²
it is equal to (L -2W)(B - 2W)
A/q
(L -2W)(B - 2W) =28
⇒LB -16W -10W +4W² =28
⇒40 -16W -10W +4W² =28
⇒4W² -26W +12 =0
⇒2W² -13W +6 =0
⇒2W²- 12W -W +6 =0
⇒2W(W- 6) -1(W-6) =0
⇒(2W-1)(W-6)=0
⇒W =0.5 m as 6m is more than the breadth
19.
area of the walls = 7560/30 = 252 m²
floor area = 1620/15 =108 m²
∴L×B = 108 m²
⇒B = 9 m
now area of four wall = 2LH + 2BH = 252
⇒2H (L +B ) =252
⇒H =252/42 = 6m
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