Math, asked by sumeshavajale, 1 month ago

Question No. 2
The convergence of which of the following method is sensitive to starting value?​

Answers

Answered by subhashkumarmahto197
8

Answer:

the convergence of Newton-Raphson method is sensitive to starting value.

Answered by bhuvna789456
0

Answer:

      The convergence of the sensitive method to starting value is  x(1)=x(0)+\frac{f(x(0))}{f'x(x(0)))}.

Step-by-step explanation:

  • In the Newton Raphson method, the approximation value is found out by x(1)=x(0)+\frac{f(x(0))}{f'x(x(0)))}.
  • Hence it depends on the initial value is x_{0}.
  • The convergence of the Newton-Raphson method is sensitive to starting value.
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