Question

  Question No. 20 A CF of differential equation is (D²+4)y=0​

Answer 1

Answer:

it's so easy why don't you do it by yoursely

ok bye take care in this Corona pendemic

Answer 2

Answer:

D^4 + 1)y = 0 -(given)

Now, from the auxillary equation f(m) = 0 , we get:

(m^4 + 1)=0

m^4 + 2m^2 - 2m^2 + 1 = 0