Question

Question no 20 and 21 solve it?

Answer 1

20. Radius = 42cm
Length of Arc = 2πrtheta/360
44 = 2×22/7×42×theta/360
Theta = 60°
Area of minor segment = πr²theta/360×1/2×r²sintheta.
= 22/7×42×42×60/360×1/2×42×42×sin60° [ sin60°= ✓3/2]

solution yahi hai isi type se Karna hai
bas data change Kar dena
_ _ ____________________
21 ans is in the pic
radius of bigger sphere(R) = 3 cm
radius of smaller balls(r) = 0.6/2 = 0.3 cm
let the number of small balls = n

n×volume of a small balls = volume of bigger sphere

Number of small balls is 1000.