Question

Question No. 23
3
In a crystal structure, oxide ion forms CCP. A2+ ion occupy one of the octahedral voids and B3+ ions are equally distributed between tetrahedral and octahedral
voids. If th of the tetrahedral voids are occupied by B3+ ion and sum of % occupancy of B3+ ion in octahedral and tetrahedral voids is then the value of x is
Answer:​

Answer 1

Answer:This may help you

Explanation:

Let A be the divalent ion and B be the trivalent ion.

In ccp unit cell the effective number of atoms occupying lattice points is-

8×1/8+6×1/2=1+3=4

Therefore,

No. of O^2−ions =4

Given that ion A occupies 1/8th of octahedral void.

Therefore,

No. of A ions =1/8×8=1

Also given that ion B occupies half of tetrahedral void.

Therefore,

No. of B ions =1/2×4=2

A:B:O=1:2:4

Therefore,

formula of oxide =AB2O4

​Hence the formula of oxide is AB2O4.