Question No. 23
If two coins are tossed simultaneously then the probability of getting at least one head is
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Answer:
3/4 is the answer for tossing two coins simultaneously
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Answer:
E6 = ( HT, TH,HH) and therefore n, (E6)=3 . Therefore,P (getting at least 1 head) =P(E6) = n(E6) / n (S) =3/4.
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