question no 28 plz needed urgently.
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volume occupied by the sphere's in the cylindrical beaker = pi* r * r* h
radius of beaker = 9 cm
height of water level that has risen = 40 cm
thus volume of all the balls= (22*9*9*40)/7
= 10182.85 cm^3
volume of each ball = (4*pi*r*r)/3
radius of sphere = 3 cm
volume of sphere= 264 cm^3
number of balls = volume of all balls/volume of each ball
= 10182.85/264
no of balls 38.57 i guess this is right
radius of beaker = 9 cm
height of water level that has risen = 40 cm
thus volume of all the balls= (22*9*9*40)/7
= 10182.85 cm^3
volume of each ball = (4*pi*r*r)/3
radius of sphere = 3 cm
volume of sphere= 264 cm^3
number of balls = volume of all balls/volume of each ball
= 10182.85/264
no of balls 38.57 i guess this is right
dhruvsh1:
great answer thanks
if you found this answer helpful pls mark as brainliest:-)
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Answer:
38.57 is the number of balls
hope it helps
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