Question No. 30
pH of 0.01 M solution of NaCN will be (given pka of HCN = 9.2)
0 12.6
0 10.6
0
2.2
O 6.4
Answers
Answered by
0
Answer:
Given that- pK
a
=9.22, C=0.5M
NaCN
0.5
+
H
2
O
⟶
NaOH
0.5
+
HCN
0.5
We know that,
pH=
2
1
[pK
w
+pK
a
+logC]
=
2
1
[14+9.22+log(05)]
pH=
2
22.92
=11.5
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