question no 36 answer???
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Answered by
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Hey mate!!
Here's your answer
We can say that 8cm + 8cm = 16cm and 15cm + 15cm = 30cm....
Since diagonals of a rhombus bisects each other
now by applying Pythagoras theorem we get,
h^2 = p^2 + b^2
h^2 = 8^2 + 15^2
h^2 = 64 + 225
h^2 = 289
h = √289
h = 17
therefore perimeter of the rhombus,
= 4a
= 4×17
= 68cm
Hope it helped you....Mark me as brainliest...
Here's your answer
We can say that 8cm + 8cm = 16cm and 15cm + 15cm = 30cm....
Since diagonals of a rhombus bisects each other
now by applying Pythagoras theorem we get,
h^2 = p^2 + b^2
h^2 = 8^2 + 15^2
h^2 = 64 + 225
h^2 = 289
h = √289
h = 17
therefore perimeter of the rhombus,
= 4a
= 4×17
= 68cm
Hope it helped you....Mark me as brainliest...
Shreya0504:
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Answered by
0
hence the answer is 68
hope it helps you
mark me as Brainliest please please
hope it helps you
mark me as Brainliest please please
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