Question

question no 4 .................​

Answer 1

Answer:

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Answer 2

Answer:

Given a general quadratic equation of the form

{\displaystyle ax^{2}+bx+c=0}ax^2+bx+c=0

with x representing an unknown, a, b and c representing constants with a ≠ 0, the quadratic formula is:

{\displaystyle x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}\ \ }

{\displaystyle x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}\ \ }

where the plus-minus symbol "±" indicates that the quadratic equation has two solutions.[2] Written separately, they become:

{\displaystyle x_{1}={\frac {-b+{\sqrt {b^{2}-4ac}}}{2a}}\quad {\text{and}}\quad x_{2}={\frac {-b-{\sqrt {b^{2}-4ac}}}{2a}}}{\displaystyle x_{1}={\frac {-b+{\sqrt {b^{2}-4ac}}}{2a}}\quad {\text{and}}\quad x_{2}={\frac {-b-{\sqrt {b^{2}-4ac}}}{2a}}}