Question

Question no.4(b).
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Answer 1

Efficiency = M.A / V.R

75/100 = M.A / 5 M.A = 3.75

M.A = Load / Effort

3.75 = Load / 1500 or 3.75 = Load / 150 Therefore,

Load = 5625 N or Load / 562.50 kgf

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