question no 5 b pls tell me
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Hi there here's your answer
Hope it helps
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Answer:let the inner circumference be c and outer circumference be C
Let the inner radius be r and outer radius be R
Step-by-step explanation:
c=2πr=176
=>r=176*7/2*22
=r=28
R=r+7=35
Area of track = π(R^2-r^2)
=(22/7)(1225-784)
=1386sq.m.
Cost of fencing =2πR*rate
=2*(22/7)*35*12
=Rs.2640
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