Question

Question no 5 fast please

Answer 1

Heya!

Here's your answer -

Given,
AE = BD
AD and BE are altitudes of the triangle where angle D & E = 90°

PT => AD = BE

Proof ->

In ΔABD and ΔABE,
AB = AB  (Common Hypotenuse)
BD = AE  (Given)
∠ADB = ∠AEB  (Right-angle)
Thus,  ΔABD is congruent to ΔABE ( RHS congruency rule)

Hence, AD = BE  (CPCT)

Hope it helps! :)

Answer 2

Given,

AE = BD

AD and BE are altitudes of the triangle where angle D & E = 90°

to proof => AD = BE

Proof ->

In ΔABD and ΔABE,

AB = AB (Common Hypotenuse)

BD = AE (Given)

∠ADB = ∠AEB (Right-angle)

Thus, ΔABD is congruent to ΔABE ......SAS TEST OF SIMILARITY

AD = BE