Question no 6 and 7
Urgent answer please
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Step-by-step explanation:
6)
Sol:
in a quadrilateral sum of square of sides =sum of square of diagonals
now,
AC^2+BD^2=AB^2+BC^2+CD^2+AD^2
AB is equal to all sides of the quadrilateral because the quadrilateral has equal sides
So, BC,CD,AD can write as AB
then,
AC^2+BD^2=AB^2+AB^2+AB^2+AB^2
AC^2+BD^2=4(AB)^2
AC^2+BD^2=4(60)^2
=4×3600
AC^2+BD^2=14400
AC Can write as BD because the diagonals lengths are equal
now,.
BD^2+BD^2=14400
2(BD)^2=14400
(BD)^2=14400/2
BD^2=7200
BD=√7200
BD=60√2
lengths of the diagonals are equal
Now, BD=AC. (Length of the diagonals are equal)
BD=60√2 cm
AC=60√2 cm
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