Math, asked by inshasaleen, 1 year ago

question no. 6 plzzzzzzz solved it fast

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ShuchiRecites: These questions are of ICSE or CBSE?

Answers

Answered by ShuchiRecites
5
\textbf{ Hello Mate! }

Please refer to attatchment.

\boxed{\textsf{ Required\:answer\:is\:9 }}

Have great future ahead!
Attachments:

inshasaleen: thnk uu so much
ShuchiRecites: Always welcome mate
inshasaleen: why have u put (-27) to the power-(2/3)
inshasaleen: sry -(-2/3)
ShuchiRecites: On reciprocal we change sign in powers.
ShuchiRecites: When it was ( 1/-27 ) ^ ( - 2 /3 ) then
ShuchiRecites: It became
ShuchiRecites: ( -27 )^- ( - 2/3 )
inshasaleen: okk thnk u
ShuchiRecites: wlcm
Answered by iHelper
6
Hello!

(-\dfrac{1}{27})^{-\tfrac{2}{3}} \\ \\ \implies (-27)^{-(-\tfrac{2}{3})} \\ \\ \implies (-27)^{\tfrac{2}{3}} \\ \\ \implies (-3^{3})^{\tfrac{2}{3}} \\ \\ \implies (-3)^{3\times \tfrac{2}{3}} \\ \\ \implies (-3)^{2} \implies \bf{9}

Cheers!
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