Question

question no 6
show tht following ​

Answer 1

∆ABE is congruent to ∆ACD

AB=AC--(1)

AD=AE--(2). (by CPCT)

From eq (1) and (2)

AB/AD=AC/AE

In ∆ADE and ∆ABC

AB/AD=AC/AE (already proved)

angle A=angleA(common)

∆ADE is similar to ∆ABC by SAS similarity criteria

hope it helps...