Question

question no. 8 plz ans

Answer 1

actually, van't Hoff's factor for any reaction ,

then, van't Hoff factor ( i ) = 1 + (n -1)α

where α is the degree of dissociation .

similarly,

now , van't Hoff' factor { i } = 1 - α + α + 2α

2.74 = 1 + 2α

1.74 = 2α

α = 0.87

Degree of dissociation in % = degree of dissociation in ratio × 100 so, % degree of dissociation = 0.87 × 100 = 87%

Answer 2

Chemical Equation

Ba(NO3)2 ------> Ba²⁺ + 2NO3⁻

At equilibrium

(moles 1-α)         α             2α

total number of ions(mole)=1-α+α+2α

1+2α       →       1+2α=i         →      α=i-1/2

2.74-1/2      →      1.74/2 =0.87  then     0.87*100=87%