Math, asked by brish16, 1 year ago

question no.8 with full process plz

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Answered by ishu6303

mark me as the brainliest pls

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ishu6303: iam really sorry bt i dont know how to solve those two questions

brish16: 12 only lol

brish16: oh ok... np

ishu6303: oh kk

brish16: can u do of parallelogram?

ishu6303: what is the question?

brish16: i am posting it... 1 min

ishu6303: kk

brish16: kar diya post

brish16: your age?

Answered by 200t

Here side of rectangle....16m×9m
therefore.....
AREA OF RECTANGLE...144m²

ATQ
AREA OF RECTANGLE= AR.( SQUARE)
therefore...
AREA OF SQUARE = 144m²..
(S)²= ( 12)²
S = 12m
therefore...
NOW PERIMETER OF RECTANGLE = 2(16+9)= 50m
ALSO PERIMETER OF SQUARE = 12×4= 48m
....
THEREFORE...
PERIMETER...OF RECTANGLE EXCEEDS THE PERIMETER...OF SQUARE BY 2m...

$<marquee > hope it helps....$
FOLLOW 200t

200t: PLEASE MARK IT AS BRANLIEST....

200t: i had so hard for it

brish16: sorry bro, i already marked 1 as brainliest.... check my profile i am posting more questions

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