Math, asked by harneet27, 9 months ago

Question no 9 and 10

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Answered by nayan505
1

Answer:

Here is ur answer for question 9... 3yrs

Step-by-step explanation:

P=2000 R=10%

M.V.=83100

LET THE NO. OF MONTHS BE n

| =Pxn(n+1)-12x2xrate

=>l=(25n2+25n)+3

M.V.=Pxn+1

=>83100=2000xn+(25n2+25n-3

=>83100x3=6000n+25n2+25n

=>249300=6025n +25n2

=>249300=25(241n+n2)

=>24930025 =241n+n2 9972=241n+n2

=>0=n2+241n-9972

=>0=n2+(277-36)n-9972

=>0=n2+277n -36n-9972

=>0=n(n+277)-36(n+277)

=>0=(n-36)(n+277)

=>0=n-36

=>n=36

THE ACCOUNT WAS HELD FOR 3 YEARS

P.S. -277 is neglected because time can not be negative.

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