Question no 9
If you’ll answer the question l will mark the answer as brailiest
Answers
Step-by-step explanation:
let X % be the rate of interest charged for 1st year
p=rupees 12000,R = x %and t = 1
interest (1)=(12000)(x)(1)/100=120x
for 2nd year
after a year, Ashok paid back rupees 4000 .
p=rupees 12000 + rupees 120 X - rupees 4000
=rupees 8000 + rupees 120 x
=interest (1)=(8000+120x)x+1/100
=(80x+1.20xsquare)
the compound interest for the second year is rupees 920
rupees (80x+1.20x square)=rupees 920
=1.20 X square + 80 x - 920 = 0
=3 X square + 200 x - 2300 = 0
=3 X square + 230 x -30 x minus 2300 =
0
x(3x+230)-10(3x+230)=0
(3x+230)(x-10)=0
x=-230/3 or x=10
2.
1st year
interest=rupees120x=rupees1200
for 2nd year
interest=rupees (80x)+(1.20xsquare)=920
the amount of depth at the end of second year is equal to addition of principal of 2nd year and interest for 2 years debt
rupees 8000 + rupees 12000 + rupees 920
=rupees 10,120
hope u like it
Answer:
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