question no17 plzzz...
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In triangle ABC ,
given DE||AC
so by basic proportionate theorem,
BE/EC=BD/DA. -(1)
In triangle ABE,
given DE||AE
so by basic proportionate theorem,
BF/FE=BD/DA. -(2)
By 1 and 2 ,
BF/FE=BE/EC
EC/BE=FE/BF
H.P
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2
hope it helps if give me a thanks
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aiswarya23:
thanku....
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