question number 12 please answer me fast
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in given fig.
Angle A=65°,B=55°
iii) in ∆ABC
A+B+C=180(angle sum property)
65+55+C=180
C=180-120
C=60°
ii) now DE is parallel to BC and DB is the transversal
we know
angle ADE=angle ABC=55°
iii) similarly EC is transversal now
so angle AED=angle ABC=60°
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