Question number 14 velocity time graph numerical.
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(a) at t=100 sec, v=20m/s
at t=200sec,v=35m/s
acceleration is a=(difference in velocities)÷time
=(35-20)÷100 (since there are 100 seconds between t=100 and t=200)
=0.15m/s^2
at t=200sec,v=35m/s
acceleration is a=(difference in velocities)÷time
=(35-20)÷100 (since there are 100 seconds between t=100 and t=200)
=0.15m/s^2
Sarah123:
Answer given as -0.075 m/s^2
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