Question

question number 2 please answer me​

Answer 1

Step-by-step explanation:

let f(x)=

${x}^{2} - x(a + b) + k$

so, if α is a root

so, f(α)=0

${ \alpha }^{2} - \alpha (a + b) + k = 0$

$k = \alpha (a + b)- { \alpha }^{2}$

$= \alpha (a + b - \alpha )$

so the equation is

${x}^{2} - x(a + b) + \alpha (a + b - \alpha ) = 0$

${x}^{2} + ( \alpha - x)(a + b) - { \alpha }^{2} = 0$

using quadratic formula, we get

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$

Using this, we can evaluate the roots.

here

$a = 1$

$b = ( \alpha - x)(a + b)$

$c = - { \alpha }^{2}$