Math, asked by sd208013, 1 year ago

question number 25
reply ultra fast

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Answered by gviswanath2003

1

∆adc=∆dcb=x
60+60+∆adc+∆dcb=360
120+x+x=360
2x=240
X=120=∆adc=∆dcb
Ab=40cm(∆adc÷∆dab=2÷1)
Ab÷dc=2÷1
Ab÷20=2÷1
Ab=40

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