Question

question number 25
reply ultra fast

Answer 1

∆adc=∆dcb=x
60+60+∆adc+∆dcb=360
120+x+x=360
2x=240
X=120=∆adc=∆dcb
Ab=40cm(∆adc÷∆dab=2÷1)
Ab÷dc=2÷1
Ab÷20=2÷1
Ab=40