Question

question number 3 please​

Answer 1

$\textbf{Answer is in Attachment !}$

I need help

Answer 2

$\bold{FACT\:\:\:FILES : }$

▶The general form of the quadratic equation is (ax²+bx+c) = 0, for any problems, but (a ≠ 0)

▶ Every quadratic equation has two and only two roots.

▶The term "b²-4ac" is called discriminant of the quadratic equation.

▶ When b²-4ac = 0, then the roots are real & equal.

▶ When b²-4ac > 0, then the roots are real and distinct.

▶ When b²-4ac < 0, then there will be no real roots.

▶ Sum of the roots of a quadratic equation is always -b/a.

▶ Product of the roots of a quadratic equation is always c/a.

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In the given equation :

1) a = (k+4)

2) b = (k+1)

3) c = 1

Given, the roots will be equal.

Hence, b² - 4 ac = 0

=> (k+1)² - 4 (k+4) × 1 = 0

=> k² + 2k + 1 - 4k - 16 = 0

=> k² - 2k - 15 = 0

=> k² - (5 - 3)k - 15 = 0

=> k (k-5) + 3 (k-5) = 0

=> (k-5) (k+3) = 0

EITHER, k = 5

OR, k = - 3

THUS, THE VALUES OF K ARE 5 AND -3.