Question

By selling a table and chair for rs1896 a trader gains 25%on table and 10% on chair if he sells them for rs 1770 he makes profit of 10%on table and 25% on chair.find the cost price of each?

Answer 1

Let C.P of the table be x.
and C.P of the chair be y.

Then, (125/100•x)+(110/100•y)=1896

25x + 22y = 35400.........(1)

Now, (110/100•x) + (125/100•y)=1770

22x + 25y = 35400........(2)

Adding eq.(1) and (2), we get

47(x+y) = 73320
x+y = 1560. ................(3)

keep x= 1200 in eq. (3),we get

1200+y = 1560
y = 360

Therefore C.P of 1 table = 1200
Therefore C.P of 1 chair = 360

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Answer 2

Answer:

C.P. of 1 table = 1200 Therefore C.P. of 1 chair = 360.

Step-by-step explanation:

Let C.P of the table be x and C.P. of the chair be y. Then,

Let C.P of the table be x and C.P. of the chair be y. Then, 25x + 22y = 37920 … (i) ⇒

Let C.P of the table be x and C.P. of the chair be y. Then, 25x + 22y = 37920 … (i) ⇒ 22x + 25y = 35400 … (ii) Adding (i) and (ii),

Let C.P of the table be x and C.P. of the chair be y. Then, 25x + 22y = 37920 … (i) ⇒ 22x + 25y = 35400 … (ii) Adding (i) and (ii),We get

Let C.P of the table be x and C.P. of the chair be y. Then, 25x + 22y = 37920 … (i) ⇒ 22x + 25y = 35400 … (ii) Adding (i) and (ii),We get47(x + y) = 73320 x + y = 1560 … (iii) Subtracting x = 1200 in (iii),

Let C.P of the table be x and C.P. of the chair be y. Then, 25x + 22y = 37920 … (i) ⇒ 22x + 25y = 35400 … (ii) Adding (i) and (ii),We get47(x + y) = 73320 x + y = 1560 … (iii) Subtracting x = 1200 in (iii),We get

Let C.P of the table be x and C.P. of the chair be y. Then, 25x + 22y = 37920 … (i) ⇒ 22x + 25y = 35400 … (ii) Adding (i) and (ii),We get47(x + y) = 73320 x + y = 1560 … (iii) Subtracting x = 1200 in (iii),We get1200 + y = 1560 y = 360. Therefore C.P. of 1 table = 1200 Therefore C.P. of 1 chair = 360.

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