the diagonal of a rhombus are 24 cm and 10 cm find area and perimeter
Answers
Answered by
1
Area = 1/2 * 24 * 10
= 120 cm^2.
Perimeter s^2 = (24/2)^2 + (10/2)^2 = 12^2 + 5^2
= 169
s = 13.
The perimeter of the rhombus = 4 * 13 = 52cm
= 120 cm^2.
Perimeter s^2 = (24/2)^2 + (10/2)^2 = 12^2 + 5^2
= 169
s = 13.
The perimeter of the rhombus = 4 * 13 = 52cm
anjugoel114:
plz mark as brainliest
Answered by
2
The area of this rhombus= 1/2*d1*d2
= 1/2*24*10
= 12*10
= 120 cm square
Perimeters of rhombus=2√d1^2+d2^2
=2√24^2+10^2
=52cm
= 1/2*24*10
= 12*10
= 120 cm square
Perimeters of rhombus=2√d1^2+d2^2
=2√24^2+10^2
=52cm
Similar questions
Social Sciences,
7 months ago
Math,
7 months ago
Hindi,
7 months ago
Math,
1 year ago
Math,
1 year ago